24h-9h^2=h

Solution for 24h-9h^2=h equation:

24h-9h^2=h

We move all terms to the left:

24h-9h^2-(h)=0

We add all the numbers together, and all the variables

-9h^2+23h=0

a = -9; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-9)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-9}=\frac{-46}{-18}
=2+5/9
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-9}=\frac{0}{-18}
=0
$